Metamath Proof Explorer


Theorem dvhopvadd

Description: The vector sum operation for the constructed full vector space H. (Contributed by NM, 21-Feb-2014) (Revised by Mario Carneiro, 6-May-2015)

Ref Expression
Hypotheses dvhvadd.h ⊢ H = LHyp ⁡ K
dvhvadd.t ⊢ T = LTrn ⁡ K ⁡ W
dvhvadd.e ⊢ E = TEndo ⁡ K ⁡ W
dvhvadd.u ⊢ U = DVecH ⁡ K ⁡ W
dvhvadd.f ⊢ D = Scalar ⁡ U
dvhvadd.s ⊢ + ˙ = + U
dvhvadd.p ⊢ ⨣ ˙ = + D
Assertion dvhopvadd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → F Q + ˙ G R = F ∘ G Q ⨣ ˙ R

Proof

Step Hyp Ref Expression
1 dvhvadd.h ⊢ H = LHyp ⁡ K
2 dvhvadd.t ⊢ T = LTrn ⁡ K ⁡ W
3 dvhvadd.e ⊢ E = TEndo ⁡ K ⁡ W
4 dvhvadd.u ⊢ U = DVecH ⁡ K ⁡ W
5 dvhvadd.f ⊢ D = Scalar ⁡ U
6 dvhvadd.s ⊢ + ˙ = + U
7 dvhvadd.p ⊢ ⨣ ˙ = + D
8 simp1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → K ∈ HL ∧ W ∈ H
9 opelxpi ⊢ F ∈ T ∧ Q ∈ E → F Q ∈ T × E
10 9 3ad2ant2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → F Q ∈ T × E
11 opelxpi ⊢ G ∈ T ∧ R ∈ E → G R ∈ T × E
12 11 3ad2ant3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → G R ∈ T × E
13 1 2 3 4 5 6 7 dvhvadd ⊢ K ∈ HL ∧ W ∈ H ∧ F Q ∈ T × E ∧ G R ∈ T × E → F Q + ˙ G R = 1 st ⁡ F Q ∘ 1 st ⁡ G R 2 nd ⁡ F Q ⨣ ˙ 2 nd ⁡ G R
14 8 10 12 13 syl12anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → F Q + ˙ G R = 1 st ⁡ F Q ∘ 1 st ⁡ G R 2 nd ⁡ F Q ⨣ ˙ 2 nd ⁡ G R
15 op1stg ⊢ F ∈ T ∧ Q ∈ E → 1 st ⁡ F Q = F
16 15 3ad2ant2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → 1 st ⁡ F Q = F
17 op1stg ⊢ G ∈ T ∧ R ∈ E → 1 st ⁡ G R = G
18 17 3ad2ant3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → 1 st ⁡ G R = G
19 16 18 coeq12d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → 1 st ⁡ F Q ∘ 1 st ⁡ G R = F ∘ G
20 op2ndg ⊢ F ∈ T ∧ Q ∈ E → 2 nd ⁡ F Q = Q
21 20 3ad2ant2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → 2 nd ⁡ F Q = Q
22 op2ndg ⊢ G ∈ T ∧ R ∈ E → 2 nd ⁡ G R = R
23 22 3ad2ant3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → 2 nd ⁡ G R = R
24 21 23 oveq12d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → 2 nd ⁡ F Q ⨣ ˙ 2 nd ⁡ G R = Q ⨣ ˙ R
25 19 24 opeq12d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → 1 st ⁡ F Q ∘ 1 st ⁡ G R 2 nd ⁡ F Q ⨣ ˙ 2 nd ⁡ G R = F ∘ G Q ⨣ ˙ R
26 14 25 eqtrd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ Q ∈ E ∧ G ∈ T ∧ R ∈ E → F Q + ˙ G R = F ∘ G Q ⨣ ˙ R