Metamath Proof Explorer


Theorem dvply2

Description: The derivative of a polynomial is a polynomial. (Contributed by Stefan O'Rear, 14-Nov-2014) (Proof shortened by Mario Carneiro, 1-Jan-2017)

Ref Expression
Assertion dvply2 ⊢ F ∈ Poly ⁡ S → ℂ D F ∈ Poly ⁡ ℂ

Proof

Step Hyp Ref Expression
1 cnring ⊢ ℂ fld ∈ Ring
2 cnfldbas ⊢ ℂ = Base ℂ fld
3 2 subrgid ⊢ ℂ fld ∈ Ring → ℂ ∈ SubRing ⁡ ℂ fld
4 1 3 ax-mp ⊢ ℂ ∈ SubRing ⁡ ℂ fld
5 plyssc ⊢ Poly ⁡ S ⊆ Poly ⁡ ℂ
6 5 sseli ⊢ F ∈ Poly ⁡ S → F ∈ Poly ⁡ ℂ
7 dvply2g ⊢ ℂ ∈ SubRing ⁡ ℂ fld ∧ F ∈ Poly ⁡ ℂ → ℂ D F ∈ Poly ⁡ ℂ
8 4 6 7 sylancr ⊢ F ∈ Poly ⁡ S → ℂ D F ∈ Poly ⁡ ℂ