Metamath Proof Explorer


Theorem ecase33d

Description: Deduction for elimination by cases. (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses ecase33d.1 ⊢ φ → ¬ ψ
ecase33d.2 ⊢ φ → ¬ χ
ecase33d.3 ⊢ φ → ψ ∨ χ ∨ θ
Assertion ecase33d ⊢ φ → θ

Proof

Step Hyp Ref Expression
1 ecase33d.1 ⊢ φ → ¬ ψ
2 ecase33d.2 ⊢ φ → ¬ χ
3 ecase33d.3 ⊢ φ → ψ ∨ χ ∨ θ
4 df-3or ⊢ ψ ∨ χ ∨ θ ↔ ψ ∨ χ ∨ θ
5 3 4 sylib ⊢ φ → ψ ∨ χ ∨ θ
6 ioran ⊢ ¬ ψ ∨ χ ↔ ¬ ψ ∧ ¬ χ
7 1 2 6 sylanbrc ⊢ φ → ¬ ψ ∨ χ
8 5 7 orcnd ⊢ φ → θ