Metamath Proof Explorer
Description: Deduction for elimination by cases. (Contributed by NM, 24-May-2013)
(Proof shortened by Wolf Lammen, 20-Sep-2024)
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|
Ref |
Expression |
|
Hypotheses |
ecase3ad.1 |
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|
|
ecase3ad.2 |
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|
|
ecase3ad.3 |
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|
Assertion |
ecase3ad |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ecase3ad.1 |
|
2 |
|
ecase3ad.2 |
|
3 |
|
ecase3ad.3 |
|
4 |
1
|
imp |
|
5 |
2
|
imp |
|
6 |
3
|
imp |
|
7 |
4 5 6
|
pm2.61ddan |
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