Metamath Proof Explorer
		
		
		
		Description:  Deduction for elimination by cases.  (Contributed by NM, 2-May-1996)
       (Proof shortened by Andrew Salmon, 7-May-2011)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | ecase3d.1 |  | 
					
						|  |  | ecase3d.2 |  | 
					
						|  |  | ecase3d.3 |  | 
				
					|  | Assertion | ecase3d |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | ecase3d.1 |  | 
						
							| 2 |  | ecase3d.2 |  | 
						
							| 3 |  | ecase3d.3 |  | 
						
							| 4 | 1 2 | jaod |  | 
						
							| 5 | 4 3 | pm2.61d |  |