Metamath Proof Explorer


Theorem eceq1d

Description: Equality theorem for equivalence class (deduction form). (Contributed by Jim Kingdon, 31-Dec-2019)

Ref Expression
Hypothesis eceq1d.1 φ A = B
Assertion eceq1d φ A C = B C

Proof

Step Hyp Ref Expression
1 eceq1d.1 φ A = B
2 eceq1 A = B A C = B C
3 1 2 syl φ A C = B C