Metamath Proof Explorer


Theorem edgfid

Description: Utility theorem: index-independent form of df-edgf . (Contributed by AV, 16-Nov-2021)

Ref Expression
Assertion edgfid ⊢ ef = Slot ef ⁡ ndx

Proof

Step Hyp Ref Expression
1 df-edgf ⊢ ef = Slot 18
2 1nn0 ⊢ 1 ∈ ℕ 0
3 8nn ⊢ 8 ∈ ℕ
4 2 3 decnncl ⊢ 18 ∈ ℕ
5 1 4 ndxid ⊢ ef = Slot ef ⁡ ndx