Metamath Proof Explorer


Theorem efiarg

Description: The exponential of the "arg" function Im o. log . (Contributed by Mario Carneiro, 25-Feb-2015)

Ref Expression
Assertion efiarg ⊢ A ∈ ℂ ∧ A ≠ 0 → e i ⁢ ℑ ⁡ log ⁡ A = A A

Proof

Step Hyp Ref Expression
1 logcl ⊢ A ∈ ℂ ∧ A ≠ 0 → log ⁡ A ∈ ℂ
2 1 recld ⊢ A ∈ ℂ ∧ A ≠ 0 → ℜ ⁡ log ⁡ A ∈ ℝ
3 2 recnd ⊢ A ∈ ℂ ∧ A ≠ 0 → ℜ ⁡ log ⁡ A ∈ ℂ
4 efsub ⊢ log ⁡ A ∈ ℂ ∧ ℜ ⁡ log ⁡ A ∈ ℂ → e log ⁡ A − ℜ ⁡ log ⁡ A = e log ⁡ A e ℜ ⁡ log ⁡ A
5 1 3 4 syl2anc ⊢ A ∈ ℂ ∧ A ≠ 0 → e log ⁡ A − ℜ ⁡ log ⁡ A = e log ⁡ A e ℜ ⁡ log ⁡ A
6 ax-icn ⊢ i ∈ ℂ
7 1 imcld ⊢ A ∈ ℂ ∧ A ≠ 0 → ℑ ⁡ log ⁡ A ∈ ℝ
8 7 recnd ⊢ A ∈ ℂ ∧ A ≠ 0 → ℑ ⁡ log ⁡ A ∈ ℂ
9 mulcl ⊢ i ∈ ℂ ∧ ℑ ⁡ log ⁡ A ∈ ℂ → i ⁢ ℑ ⁡ log ⁡ A ∈ ℂ
10 6 8 9 sylancr ⊢ A ∈ ℂ ∧ A ≠ 0 → i ⁢ ℑ ⁡ log ⁡ A ∈ ℂ
11 1 replimd ⊢ A ∈ ℂ ∧ A ≠ 0 → log ⁡ A = ℜ ⁡ log ⁡ A + i ⁢ ℑ ⁡ log ⁡ A
12 3 10 11 mvrladdd ⊢ A ∈ ℂ ∧ A ≠ 0 → log ⁡ A − ℜ ⁡ log ⁡ A = i ⁢ ℑ ⁡ log ⁡ A
13 12 fveq2d ⊢ A ∈ ℂ ∧ A ≠ 0 → e log ⁡ A − ℜ ⁡ log ⁡ A = e i ⁢ ℑ ⁡ log ⁡ A
14 eflog ⊢ A ∈ ℂ ∧ A ≠ 0 → e log ⁡ A = A
15 relog ⊢ A ∈ ℂ ∧ A ≠ 0 → ℜ ⁡ log ⁡ A = log ⁡ A
16 15 fveq2d ⊢ A ∈ ℂ ∧ A ≠ 0 → e ℜ ⁡ log ⁡ A = e log ⁡ A
17 abscl ⊢ A ∈ ℂ → A ∈ ℝ
18 17 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 → A ∈ ℝ
19 18 recnd ⊢ A ∈ ℂ ∧ A ≠ 0 → A ∈ ℂ
20 absrpcl ⊢ A ∈ ℂ ∧ A ≠ 0 → A ∈ ℝ +
21 20 rpne0d ⊢ A ∈ ℂ ∧ A ≠ 0 → A ≠ 0
22 eflog ⊢ A ∈ ℂ ∧ A ≠ 0 → e log ⁡ A = A
23 19 21 22 syl2anc ⊢ A ∈ ℂ ∧ A ≠ 0 → e log ⁡ A = A
24 16 23 eqtrd ⊢ A ∈ ℂ ∧ A ≠ 0 → e ℜ ⁡ log ⁡ A = A
25 14 24 oveq12d ⊢ A ∈ ℂ ∧ A ≠ 0 → e log ⁡ A e ℜ ⁡ log ⁡ A = A A
26 5 13 25 3eqtr3d ⊢ A ∈ ℂ ∧ A ≠ 0 → e i ⁢ ℑ ⁡ log ⁡ A = A A