Metamath Proof Explorer


Theorem efmndbasf

Description: Elements in the monoid of endofunctions on A are functions from A into itself. (Contributed by AV, 27-Jan-2024)

Ref Expression
Hypotheses efmndbas.g ⊢ G = EndoFMnd ⁡ A
efmndbas.b ⊢ B = Base G
Assertion efmndbasf ⊢ F ∈ B → F : A ⟶ A

Proof

Step Hyp Ref Expression
1 efmndbas.g ⊢ G = EndoFMnd ⁡ A
2 efmndbas.b ⊢ B = Base G
3 1 2 elefmndbas2 ⊢ F ∈ B → F ∈ B ↔ F : A ⟶ A
4 3 ibi ⊢ F ∈ B → F : A ⟶ A