Metamath Proof Explorer


Theorem ehl0

Description: The Euclidean space of dimension 0 consists of the neutral element only. (Contributed by AV, 12-Feb-2023)

Ref Expression
Hypotheses ehl0base.e ⊢ E = 𝔼 hil ⁡ 0
ehl0base.0 ⊢ 0 ˙ = 0 E
Assertion ehl0 ⊢ Base E = 0 ˙

Proof

Step Hyp Ref Expression
1 ehl0base.e ⊢ E = 𝔼 hil ⁡ 0
2 ehl0base.0 ⊢ 0 ˙ = 0 E
3 1 ehl0base ⊢ Base E = ∅
4 ovex ⊢ 1 … 0 ∈ V
5 0nn0 ⊢ 0 ∈ ℕ 0
6 1 ehlval ⊢ 0 ∈ ℕ 0 → E = 1 … 0
7 5 6 ax-mp ⊢ E = 1 … 0
8 fz10 ⊢ 1 … 0 = ∅
9 8 xpeq1i ⊢ 1 … 0 × 0 = ∅ × 0
10 9 eqcomi ⊢ ∅ × 0 = 1 … 0 × 0
11 7 10 rrx0 ⊢ 1 … 0 ∈ V → 0 E = ∅ × 0
12 4 11 ax-mp ⊢ 0 E = ∅ × 0
13 2 12 eqtri ⊢ 0 ˙ = ∅ × 0
14 0xp ⊢ ∅ × 0 = ∅
15 13 14 eqtri ⊢ 0 ˙ = ∅
16 15 eqcomi ⊢ ∅ = 0 ˙
17 16 sneqi ⊢ ∅ = 0 ˙
18 3 17 eqtri ⊢ Base E = 0 ˙