Metamath Proof Explorer


Theorem elab3gf

Description: Membership in a class abstraction, with a weaker antecedent than elabgf . (Contributed by NM, 6-Sep-2011)

Ref Expression
Hypotheses elab3gf.1 ⊢ Ⅎ _ x A
elab3gf.2 ⊢ Ⅎ x ψ
elab3gf.3 ⊢ x = A → φ ↔ ψ
Assertion elab3gf ⊢ ψ → A ∈ B → A ∈ x | φ ↔ ψ

Proof

Step Hyp Ref Expression
1 elab3gf.1 ⊢ Ⅎ _ x A
2 elab3gf.2 ⊢ Ⅎ x ψ
3 elab3gf.3 ⊢ x = A → φ ↔ ψ
4 1 2 3 elabgf ⊢ A ∈ x | φ → A ∈ x | φ ↔ ψ
5 4 ibi ⊢ A ∈ x | φ → ψ
6 pm2.21 ⊢ ¬ ψ → ψ → A ∈ x | φ
7 5 6 impbid2 ⊢ ¬ ψ → A ∈ x | φ ↔ ψ
8 1 2 3 elabgf ⊢ A ∈ B → A ∈ x | φ ↔ ψ
9 7 8 ja ⊢ ψ → A ∈ B → A ∈ x | φ ↔ ψ