Metamath Proof Explorer
Description: Membership in a class abstraction, using implicit substitution.
Deduction version of elab . (Contributed by GG, 12-Oct-2024)
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Ref |
Expression |
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Hypotheses |
elabd3.ex |
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elabd3.is |
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Assertion |
elabd3 |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
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elabd3.ex |
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| 2 |
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elabd3.is |
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| 3 |
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eqidd |
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| 4 |
1 3 2
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elabd2 |
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