Metamath Proof Explorer


Theorem eldifsnbd

Description: Membership in a set with an element removed implies non-equality with that element. (Contributed by Thierry Arnoux, 13-Jul-2026)

Ref Expression
Hypothesis eldifsnbd.1 φ A B C
Assertion eldifsnbd φ A C

Proof

Step Hyp Ref Expression
1 eldifsnbd.1 φ A B C
2 eldifsn A B C A B A C
3 1 2 sylib φ A B A C
4 3 simprd φ A C