Metamath Proof Explorer


Theorem eldifsnbd

Description: Membership in a set with an element removed implies non-equality with that element. (Contributed by Thierry Arnoux, 13-Jul-2026)

Ref Expression
Hypothesis eldifsnbd.1 ⊢ φ → A ∈ B ∖ C
Assertion eldifsnbd ⊢ φ → A ≠ C

Proof

Step Hyp Ref Expression
1 eldifsnbd.1 ⊢ φ → A ∈ B ∖ C
2 eldifsn ⊢ A ∈ B ∖ C ↔ A ∈ B ∧ A ≠ C
3 1 2 sylib ⊢ φ → A ∈ B ∧ A ≠ C
4 3 simprd ⊢ φ → A ≠ C