Metamath Proof Explorer


Theorem elfvdm

Description: If a function value has a member, then the argument belongs to the domain. (An artifact of our function value definition.) (Contributed by NM, 12-Feb-2007) (Proof shortened by BJ, 22-Oct-2022)

Ref Expression
Assertion elfvdm ⊢ A ∈ F ⁡ B → B ∈ dom ⁡ F

Proof

Step Hyp Ref Expression
1 n0i ⊢ A ∈ F ⁡ B → ¬ F ⁡ B = ∅
2 ndmfv ⊢ ¬ B ∈ dom ⁡ F → F ⁡ B = ∅
3 1 2 nsyl2 ⊢ A ∈ F ⁡ B → B ∈ dom ⁡ F