Metamath Proof Explorer


Theorem elfzomelpfzo

Description: An integer increased by another integer is an element of a half-open integer range if and only if the integer is contained in the half-open integer range with bounds decreased by the other integer. (Contributed by Alexander van der Vekens, 30-Mar-2018)

Ref Expression
Assertion elfzomelpfzo ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K ∈ M − L ..^ N − L ↔ K + L ∈ M ..^ N

Proof

Step Hyp Ref Expression
1 zsubcl ⊢ M ∈ ℤ ∧ L ∈ ℤ → M − L ∈ ℤ
2 1 ad2ant2rl ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → M − L ∈ ℤ
3 simpl ⊢ M ∈ ℤ ∧ N ∈ ℤ → M ∈ ℤ
4 3 adantr ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → M ∈ ℤ
5 2 4 2thd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → M − L ∈ ℤ ↔ M ∈ ℤ
6 simpl ⊢ K ∈ ℤ ∧ L ∈ ℤ → K ∈ ℤ
7 6 adantl ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K ∈ ℤ
8 zaddcl ⊢ K ∈ ℤ ∧ L ∈ ℤ → K + L ∈ ℤ
9 8 adantl ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K + L ∈ ℤ
10 7 9 2thd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K ∈ ℤ ↔ K + L ∈ ℤ
11 zre ⊢ M ∈ ℤ → M ∈ ℝ
12 11 adantr ⊢ M ∈ ℤ ∧ N ∈ ℤ → M ∈ ℝ
13 12 adantr ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → M ∈ ℝ
14 zre ⊢ L ∈ ℤ → L ∈ ℝ
15 14 adantl ⊢ K ∈ ℤ ∧ L ∈ ℤ → L ∈ ℝ
16 15 adantl ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → L ∈ ℝ
17 zre ⊢ K ∈ ℤ → K ∈ ℝ
18 17 adantr ⊢ K ∈ ℤ ∧ L ∈ ℤ → K ∈ ℝ
19 18 adantl ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K ∈ ℝ
20 13 16 19 lesubaddd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → M − L ≤ K ↔ M ≤ K + L
21 5 10 20 3anbi123d ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → M − L ∈ ℤ ∧ K ∈ ℤ ∧ M − L ≤ K ↔ M ∈ ℤ ∧ K + L ∈ ℤ ∧ M ≤ K + L
22 eluz2 ⊢ K ∈ ℤ ≥ M − L ↔ M − L ∈ ℤ ∧ K ∈ ℤ ∧ M − L ≤ K
23 eluz2 ⊢ K + L ∈ ℤ ≥ M ↔ M ∈ ℤ ∧ K + L ∈ ℤ ∧ M ≤ K + L
24 21 22 23 3bitr4g ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K ∈ ℤ ≥ M − L ↔ K + L ∈ ℤ ≥ M
25 zsubcl ⊢ N ∈ ℤ ∧ L ∈ ℤ → N − L ∈ ℤ
26 25 ad2ant2l ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → N − L ∈ ℤ
27 simplr ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → N ∈ ℤ
28 26 27 2thd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → N − L ∈ ℤ ↔ N ∈ ℤ
29 zre ⊢ N ∈ ℤ → N ∈ ℝ
30 29 adantl ⊢ M ∈ ℤ ∧ N ∈ ℤ → N ∈ ℝ
31 30 adantr ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → N ∈ ℝ
32 19 16 31 ltaddsubd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K + L < N ↔ K < N − L
33 32 bicomd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K < N − L ↔ K + L < N
34 24 28 33 3anbi123d ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K ∈ ℤ ≥ M − L ∧ N − L ∈ ℤ ∧ K < N − L ↔ K + L ∈ ℤ ≥ M ∧ N ∈ ℤ ∧ K + L < N
35 elfzo2 ⊢ K ∈ M − L ..^ N − L ↔ K ∈ ℤ ≥ M − L ∧ N − L ∈ ℤ ∧ K < N − L
36 elfzo2 ⊢ K + L ∈ M ..^ N ↔ K + L ∈ ℤ ≥ M ∧ N ∈ ℤ ∧ K + L < N
37 34 35 36 3bitr4g ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ L ∈ ℤ → K ∈ M − L ..^ N − L ↔ K + L ∈ M ..^ N