Metamath Proof Explorer


Theorem eliccd

Description: Membership in a closed real interval. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses eliccd.1 ⊢ φ → A ∈ ℝ
eliccd.2 ⊢ φ → B ∈ ℝ
eliccd.3 ⊢ φ → C ∈ ℝ
eliccd.4 ⊢ φ → A ≤ C
eliccd.5 ⊢ φ → C ≤ B
Assertion eliccd ⊢ φ → C ∈ A B

Proof

Step Hyp Ref Expression
1 eliccd.1 ⊢ φ → A ∈ ℝ
2 eliccd.2 ⊢ φ → B ∈ ℝ
3 eliccd.3 ⊢ φ → C ∈ ℝ
4 eliccd.4 ⊢ φ → A ≤ C
5 eliccd.5 ⊢ φ → C ≤ B
6 elicc2 ⊢ A ∈ ℝ ∧ B ∈ ℝ → C ∈ A B ↔ C ∈ ℝ ∧ A ≤ C ∧ C ≤ B
7 1 2 6 syl2anc ⊢ φ → C ∈ A B ↔ C ∈ ℝ ∧ A ≤ C ∧ C ≤ B
8 3 4 5 7 mpbir3and ⊢ φ → C ∈ A B