Metamath Proof Explorer


Theorem elintrabg

Description: Membership in the intersection of a class abstraction. (Contributed by NM, 17-Feb-2007)

Ref Expression
Assertion elintrabg ⊢ A ∈ V → A ∈ ⋂ x ∈ B | φ ↔ ∀ x ∈ B φ → A ∈ x

Proof

Step Hyp Ref Expression
1 eleq1 ⊢ y = A → y ∈ ⋂ x ∈ B | φ ↔ A ∈ ⋂ x ∈ B | φ
2 eleq1 ⊢ y = A → y ∈ x ↔ A ∈ x
3 2 imbi2d ⊢ y = A → φ → y ∈ x ↔ φ → A ∈ x
4 3 ralbidv ⊢ y = A → ∀ x ∈ B φ → y ∈ x ↔ ∀ x ∈ B φ → A ∈ x
5 vex ⊢ y ∈ V
6 5 elintrab ⊢ y ∈ ⋂ x ∈ B | φ ↔ ∀ x ∈ B φ → y ∈ x
7 1 4 6 vtoclbg ⊢ A ∈ V → A ∈ ⋂ x ∈ B | φ ↔ ∀ x ∈ B φ → A ∈ x