Metamath Proof Explorer


Theorem elrabrd

Description: Deduction version of elrab , just like elrabd , but backwards direction. (Contributed by Thierry Arnoux, 15-Jan-2026)

Ref Expression
Hypotheses elrabrd.1 ⊢ x = A → ψ ↔ χ
elrabrd.2 ⊢ φ → A ∈ x ∈ B | ψ
Assertion elrabrd ⊢ φ → χ

Proof

Step Hyp Ref Expression
1 elrabrd.1 ⊢ x = A → ψ ↔ χ
2 elrabrd.2 ⊢ φ → A ∈ x ∈ B | ψ
3 1 elrab ⊢ A ∈ x ∈ B | ψ ↔ A ∈ B ∧ χ
4 2 3 sylib ⊢ φ → A ∈ B ∧ χ
5 4 simprd ⊢ φ → χ