Metamath Proof Explorer


Theorem eqfnov2

Description: Two operators with the same domain are equal iff their values at each point in the domain are equal. (Contributed by Jeff Madsen, 7-Jun-2010)

Ref Expression
Assertion eqfnov2 ⊢ F Fn A × B ∧ G Fn A × B → F = G ↔ ∀ x ∈ A ∀ y ∈ B x F y = x G y

Proof

Step Hyp Ref Expression
1 eqfnov ⊢ F Fn A × B ∧ G Fn A × B → F = G ↔ A × B = A × B ∧ ∀ x ∈ A ∀ y ∈ B x F y = x G y
2 simpr ⊢ A × B = A × B ∧ ∀ x ∈ A ∀ y ∈ B x F y = x G y → ∀ x ∈ A ∀ y ∈ B x F y = x G y
3 eqidd ⊢ ∀ x ∈ A ∀ y ∈ B x F y = x G y → A × B = A × B
4 3 ancri ⊢ ∀ x ∈ A ∀ y ∈ B x F y = x G y → A × B = A × B ∧ ∀ x ∈ A ∀ y ∈ B x F y = x G y
5 2 4 impbii ⊢ A × B = A × B ∧ ∀ x ∈ A ∀ y ∈ B x F y = x G y ↔ ∀ x ∈ A ∀ y ∈ B x F y = x G y
6 1 5 bitrdi ⊢ F Fn A × B ∧ G Fn A × B → F = G ↔ ∀ x ∈ A ∀ y ∈ B x F y = x G y