Metamath Proof Explorer


Theorem eqlkr4

Description: Two functionals with the same kernel are the same up to a constant. (Contributed by NM, 4-Feb-2015)

Ref Expression
Hypotheses eqlkr4.s ⊢ S = Scalar ⁡ W
eqlkr4.r ⊢ R = Base S
eqlkr4.f ⊢ F = LFnl ⁡ W
eqlkr4.k ⊢ K = LKer ⁡ W
eqlkr4.d ⊢ D = LDual ⁡ W
eqlkr4.t ⊢ · ˙ = ⋅ D
eqlkr4.w ⊢ φ → W ∈ LVec
eqlkr4.g ⊢ φ → G ∈ F
eqlkr4.h ⊢ φ → H ∈ F
eqlkr4.e ⊢ φ → K ⁡ G = K ⁡ H
Assertion eqlkr4 ⊢ φ → ∃ r ∈ R H = r · ˙ G

Proof

Step Hyp Ref Expression
1 eqlkr4.s ⊢ S = Scalar ⁡ W
2 eqlkr4.r ⊢ R = Base S
3 eqlkr4.f ⊢ F = LFnl ⁡ W
4 eqlkr4.k ⊢ K = LKer ⁡ W
5 eqlkr4.d ⊢ D = LDual ⁡ W
6 eqlkr4.t ⊢ · ˙ = ⋅ D
7 eqlkr4.w ⊢ φ → W ∈ LVec
8 eqlkr4.g ⊢ φ → G ∈ F
9 eqlkr4.h ⊢ φ → H ∈ F
10 eqlkr4.e ⊢ φ → K ⁡ G = K ⁡ H
11 eqid ⊢ ⋅ S = ⋅ S
12 eqid ⊢ Base W = Base W
13 1 2 11 12 3 4 eqlkr2 ⊢ W ∈ LVec ∧ G ∈ F ∧ H ∈ F ∧ K ⁡ G = K ⁡ H → ∃ r ∈ R H = G ⋅ S f Base W × r
14 7 8 9 10 13 syl121anc ⊢ φ → ∃ r ∈ R H = G ⋅ S f Base W × r
15 7 adantr ⊢ φ ∧ r ∈ R → W ∈ LVec
16 simpr ⊢ φ ∧ r ∈ R → r ∈ R
17 8 adantr ⊢ φ ∧ r ∈ R → G ∈ F
18 3 12 1 2 11 5 6 15 16 17 ldualvs ⊢ φ ∧ r ∈ R → r · ˙ G = G ⋅ S f Base W × r
19 18 eqeq2d ⊢ φ ∧ r ∈ R → H = r · ˙ G ↔ H = G ⋅ S f Base W × r
20 19 rexbidva ⊢ φ → ∃ r ∈ R H = r · ˙ G ↔ ∃ r ∈ R H = G ⋅ S f Base W × r
21 14 20 mpbird ⊢ φ → ∃ r ∈ R H = r · ˙ G