Metamath Proof Explorer


Theorem eqrdv

Description: Deduce equality of classes from equivalence of membership. (Contributed by NM, 17-Mar-1996)

Ref Expression
Hypothesis eqrdv.1 φ x A x B
Assertion eqrdv φ A = B

Proof

Step Hyp Ref Expression
1 eqrdv.1 φ x A x B
2 1 alrimiv φ x x A x B
3 dfcleq A = B x x A x B
4 2 3 sylibr φ A = B