Metamath Proof Explorer


Theorem eqtr4id

Description: An equality transitivity deduction. (Contributed by NM, 29-Mar-1998)

Ref Expression
Hypotheses eqtr4id.2 A = B
eqtr4id.1 φ C = B
Assertion eqtr4id φ A = C

Proof

Step Hyp Ref Expression
1 eqtr4id.2 A = B
2 eqtr4id.1 φ C = B
3 1 eqcomi B = A
4 2 3 eqtr2di φ A = C