Metamath Proof Explorer


Theorem etransclem1

Description: H is a function. (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypotheses etransclem1.x ⊢ φ → X ⊆ ℂ
etransclem1.p ⊢ φ → P ∈ ℕ
etransclem1.h ⊢ H = j ∈ 0 … M ⟼ x ∈ X ⟼ x − j if j = 0 P − 1 P
etransclem1.j ⊢ φ → J ∈ 0 … M
Assertion etransclem1 ⊢ φ → H ⁡ J : X ⟶ ℂ

Proof

Step Hyp Ref Expression
1 etransclem1.x ⊢ φ → X ⊆ ℂ
2 etransclem1.p ⊢ φ → P ∈ ℕ
3 etransclem1.h ⊢ H = j ∈ 0 … M ⟼ x ∈ X ⟼ x − j if j = 0 P − 1 P
4 etransclem1.j ⊢ φ → J ∈ 0 … M
5 1 sselda ⊢ φ ∧ x ∈ X → x ∈ ℂ
6 4 elfzelzd ⊢ φ → J ∈ ℤ
7 6 zcnd ⊢ φ → J ∈ ℂ
8 7 adantr ⊢ φ ∧ x ∈ X → J ∈ ℂ
9 5 8 subcld ⊢ φ ∧ x ∈ X → x − J ∈ ℂ
10 nnm1nn0 ⊢ P ∈ ℕ → P − 1 ∈ ℕ 0
11 2 10 syl ⊢ φ → P − 1 ∈ ℕ 0
12 2 nnnn0d ⊢ φ → P ∈ ℕ 0
13 11 12 ifcld ⊢ φ → if J = 0 P − 1 P ∈ ℕ 0
14 13 adantr ⊢ φ ∧ x ∈ X → if J = 0 P − 1 P ∈ ℕ 0
15 9 14 expcld ⊢ φ ∧ x ∈ X → x − J if J = 0 P − 1 P ∈ ℂ
16 eqid ⊢ x ∈ X ⟼ x − J if J = 0 P − 1 P = x ∈ X ⟼ x − J if J = 0 P − 1 P
17 15 16 fmptd ⊢ φ → x ∈ X ⟼ x − J if J = 0 P − 1 P : X ⟶ ℂ
18 oveq2 ⊢ j = n → x − j = x − n
19 eqeq1 ⊢ j = n → j = 0 ↔ n = 0
20 19 ifbid ⊢ j = n → if j = 0 P − 1 P = if n = 0 P − 1 P
21 18 20 oveq12d ⊢ j = n → x − j if j = 0 P − 1 P = x − n if n = 0 P − 1 P
22 21 mpteq2dv ⊢ j = n → x ∈ X ⟼ x − j if j = 0 P − 1 P = x ∈ X ⟼ x − n if n = 0 P − 1 P
23 22 cbvmptv ⊢ j ∈ 0 … M ⟼ x ∈ X ⟼ x − j if j = 0 P − 1 P = n ∈ 0 … M ⟼ x ∈ X ⟼ x − n if n = 0 P − 1 P
24 3 23 eqtri ⊢ H = n ∈ 0 … M ⟼ x ∈ X ⟼ x − n if n = 0 P − 1 P
25 oveq2 ⊢ n = J → x − n = x − J
26 eqeq1 ⊢ n = J → n = 0 ↔ J = 0
27 26 ifbid ⊢ n = J → if n = 0 P − 1 P = if J = 0 P − 1 P
28 25 27 oveq12d ⊢ n = J → x − n if n = 0 P − 1 P = x − J if J = 0 P − 1 P
29 28 mpteq2dv ⊢ n = J → x ∈ X ⟼ x − n if n = 0 P − 1 P = x ∈ X ⟼ x − J if J = 0 P − 1 P
30 cnex ⊢ ℂ ∈ V
31 30 ssex ⊢ X ⊆ ℂ → X ∈ V
32 mptexg ⊢ X ∈ V → x ∈ X ⟼ x − J if J = 0 P − 1 P ∈ V
33 1 31 32 3syl ⊢ φ → x ∈ X ⟼ x − J if J = 0 P − 1 P ∈ V
34 24 29 4 33 fvmptd3 ⊢ φ → H ⁡ J = x ∈ X ⟼ x − J if J = 0 P − 1 P
35 34 feq1d ⊢ φ → H ⁡ J : X ⟶ ℂ ↔ x ∈ X ⟼ x − J if J = 0 P − 1 P : X ⟶ ℂ
36 17 35 mpbird ⊢ φ → H ⁡ J : X ⟶ ℂ