Metamath Proof Explorer


Theorem etransclem30

Description: The N -th derivative of F . (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypotheses etransclem30.s ⊢ φ → S ∈ ℝ ℂ
etransclem30.a ⊢ φ → X ∈ TopOpen ⁡ ℂ fld ↾ 𝑡 S
etransclem30.p ⊢ φ → P ∈ ℕ
etransclem30.m ⊢ φ → M ∈ ℕ 0
etransclem30.f ⊢ F = x ∈ X ⟼ x P − 1 ⁢ ∏ j = 1 M x − j P
etransclem30.n ⊢ φ → N ∈ ℕ 0
etransclem30.h ⊢ H = j ∈ 0 … M ⟼ x ∈ X ⟼ x − j if j = 0 P − 1 P
etransclem30.c ⊢ C = n ∈ ℕ 0 ⟼ c ∈ 0 … n 0 … M | ∑ j = 0 M c ⁡ j = n
Assertion etransclem30 ⊢ φ → S D n F ⁡ N = x ∈ X ⟼ ∑ c ∈ C ⁡ N N ! ∏ j = 0 M c ⁡ j ! ⁢ ∏ j = 0 M S D n H ⁡ j ⁡ c ⁡ j ⁡ x

Proof

Step Hyp Ref Expression
1 etransclem30.s ⊢ φ → S ∈ ℝ ℂ
2 etransclem30.a ⊢ φ → X ∈ TopOpen ⁡ ℂ fld ↾ 𝑡 S
3 etransclem30.p ⊢ φ → P ∈ ℕ
4 etransclem30.m ⊢ φ → M ∈ ℕ 0
5 etransclem30.f ⊢ F = x ∈ X ⟼ x P − 1 ⁢ ∏ j = 1 M x − j P
6 etransclem30.n ⊢ φ → N ∈ ℕ 0
7 etransclem30.h ⊢ H = j ∈ 0 … M ⟼ x ∈ X ⟼ x − j if j = 0 P − 1 P
8 etransclem30.c ⊢ C = n ∈ ℕ 0 ⟼ c ∈ 0 … n 0 … M | ∑ j = 0 M c ⁡ j = n
9 eqid ⊢ x ∈ X ⟼ ∏ j = 0 M H ⁡ j ⁡ x = x ∈ X ⟼ ∏ j = 0 M H ⁡ j ⁡ x
10 1 2 3 4 5 6 7 8 9 etransclem29 ⊢ φ → S D n F ⁡ N = x ∈ X ⟼ ∑ c ∈ C ⁡ N N ! ∏ j = 0 M c ⁡ j ! ⁢ ∏ j = 0 M S D n H ⁡ j ⁡ c ⁡ j ⁡ x