Metamath Proof Explorer


Theorem etransclem42

Description: The N -th derivative of F applied to J is an integer. (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypotheses etransclem42.s ⊢ φ → S ∈ ℝ ℂ
etransclem42.x ⊢ φ → X ∈ TopOpen ⁡ ℂ fld ↾ 𝑡 S
etransclem42.p ⊢ φ → P ∈ ℕ
etransclem42.m ⊢ φ → M ∈ ℕ 0
etransclem42.f ⊢ F = x ∈ X ⟼ x P − 1 ⁢ ∏ j = 1 M x − j P
etransclem42.n ⊢ φ → N ∈ ℕ 0
etransclem42.jx ⊢ φ → J ∈ X
etransclem42.jz ⊢ φ → J ∈ ℤ
Assertion etransclem42 ⊢ φ → S D n F ⁡ N ⁡ J ∈ ℤ

Proof

Step Hyp Ref Expression
1 etransclem42.s ⊢ φ → S ∈ ℝ ℂ
2 etransclem42.x ⊢ φ → X ∈ TopOpen ⁡ ℂ fld ↾ 𝑡 S
3 etransclem42.p ⊢ φ → P ∈ ℕ
4 etransclem42.m ⊢ φ → M ∈ ℕ 0
5 etransclem42.f ⊢ F = x ∈ X ⟼ x P − 1 ⁢ ∏ j = 1 M x − j P
6 etransclem42.n ⊢ φ → N ∈ ℕ 0
7 etransclem42.jx ⊢ φ → J ∈ X
8 etransclem42.jz ⊢ φ → J ∈ ℤ
9 etransclem5 ⊢ k ∈ 0 … M ⟼ y ∈ X ⟼ y − k if k = 0 P − 1 P = j ∈ 0 … M ⟼ x ∈ X ⟼ x − j if j = 0 P − 1 P
10 etransclem11 ⊢ m ∈ ℕ 0 ⟼ d ∈ 0 … m 0 … M | ∑ k = 0 M d ⁡ k = m = n ∈ ℕ 0 ⟼ c ∈ 0 … n 0 … M | ∑ j = 0 M c ⁡ j = n
11 1 2 3 4 5 6 9 7 8 10 etransclem36 ⊢ φ → S D n F ⁡ N ⁡ J ∈ ℤ