Metamath Proof Explorer


Theorem ex-decpmul

Description: Example usage of decpmul . This proof is significantly longer than 235t711 . There is more unnecessary carrying compared to 235t711 . Although saving 5 visual steps, using mulcomli early on increases the compressed proof length. (Contributed by Steven Nguyen, 10-Dec-2022) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Assertion ex-decpmul ⊢ 235 ⋅ 711 = 167085

Proof

Step Hyp Ref Expression
1 2nn0 ⊢ 2 ∈ ℕ 0
2 3nn0 ⊢ 3 ∈ ℕ 0
3 1 2 deccl ⊢ 23 ∈ ℕ 0
4 5nn0 ⊢ 5 ∈ ℕ 0
5 7nn0 ⊢ 7 ∈ ℕ 0
6 1nn0 ⊢ 1 ∈ ℕ 0
7 5 6 deccl ⊢ 71 ∈ ℕ 0
8 eqid ⊢ 71 = 71
9 6nn0 ⊢ 6 ∈ ℕ 0
10 6 9 deccl ⊢ 16 ∈ ℕ 0
11 eqid ⊢ 23 = 23
12 4nn0 ⊢ 4 ∈ ℕ 0
13 7cn ⊢ 7 ∈ ℂ
14 2cn ⊢ 2 ∈ ℂ
15 7t2e14 ⊢ 7 ⋅ 2 = 14
16 13 14 15 mulcomli ⊢ 2 ⋅ 7 = 14
17 4p2e6 ⊢ 4 + 2 = 6
18 6 12 1 16 17 decaddi ⊢ 2 ⋅ 7 + 2 = 16
19 3cn ⊢ 3 ∈ ℂ
20 7t3e21 ⊢ 7 ⋅ 3 = 21
21 13 19 20 mulcomli ⊢ 3 ⋅ 7 = 21
22 5 1 2 11 6 1 18 21 decmul1c ⊢ 23 ⋅ 7 = 161
23 1p2e3 ⊢ 1 + 2 = 3
24 10 6 1 22 23 decaddi ⊢ 23 ⋅ 7 + 2 = 163
25 3 nn0cni ⊢ 23 ∈ ℂ
26 25 mulridi ⊢ 23 ⋅ 1 = 23
27 3 5 6 8 2 1 24 26 decmul2c ⊢ 23 ⋅ 71 = 1633
28 2 4 deccl ⊢ 35 ∈ ℕ 0
29 7 nn0cni ⊢ 71 ∈ ℂ
30 5cn ⊢ 5 ∈ ℂ
31 7t5e35 ⊢ 7 ⋅ 5 = 35
32 30 mullidi ⊢ 1 ⋅ 5 = 5
33 4 5 6 8 31 32 decmul1 ⊢ 71 ⋅ 5 = 355
34 29 30 33 mulcomli ⊢ 5 ⋅ 71 = 355
35 28 nn0cni ⊢ 35 ∈ ℂ
36 eqid ⊢ 35 = 35
37 5p2e7 ⊢ 5 + 2 = 7
38 2 4 1 36 37 decaddi ⊢ 35 + 2 = 37
39 35 14 38 addcomli ⊢ 2 + 35 = 37
40 5p3e8 ⊢ 5 + 3 = 8
41 30 19 40 addcomli ⊢ 3 + 5 = 8
42 1 2 28 4 26 34 39 41 decadd ⊢ 23 ⋅ 1 + 5 ⋅ 71 = 378
43 30 mulridi ⊢ 5 ⋅ 1 = 5
44 4 dec0h ⊢ 5 = 05
45 43 44 eqtri ⊢ 5 ⋅ 1 = 05
46 10 2 deccl ⊢ 163 ∈ ℕ 0
47 46 2 deccl ⊢ 1633 ∈ ℕ 0
48 0nn0 ⊢ 0 ∈ ℕ 0
49 2 5 deccl ⊢ 37 ∈ ℕ 0
50 8nn0 ⊢ 8 ∈ ℕ 0
51 eqid ⊢ 16330 = 16330
52 eqid ⊢ 378 = 378
53 eqid ⊢ 1633 = 1633
54 eqid ⊢ 37 = 37
55 eqid ⊢ 163 = 163
56 3p3e6 ⊢ 3 + 3 = 6
57 10 2 2 55 56 decaddi ⊢ 163 + 3 = 166
58 6p1e7 ⊢ 6 + 1 = 7
59 10 9 6 57 58 decaddi ⊢ 163 + 3 + 1 = 167
60 7p3e10 ⊢ 7 + 3 = 10
61 13 19 60 addcomli ⊢ 3 + 7 = 10
62 46 2 2 5 53 54 59 61 decaddc2 ⊢ 1633 + 37 = 1670
63 8cn ⊢ 8 ∈ ℂ
64 63 addlidi ⊢ 0 + 8 = 8
65 47 48 49 50 51 52 62 64 decadd ⊢ 16330 + 378 = 16708
66 3 4 7 6 27 42 45 65 48 4 decpmul ⊢ 235 ⋅ 711 = 167085