Metamath Proof Explorer


Theorem ex-dif

Description: Example for df-dif . Example by David A. Wheeler. (Contributed by Mario Carneiro, 6-May-2015)

Ref Expression
Assertion ex-dif ⊢ 1 3 ∖ 1 8 = 3

Proof

Step Hyp Ref Expression
1 df-pr ⊢ 1 3 = 1 ∪ 3
2 1 difeq1i ⊢ 1 3 ∖ 1 8 = 1 ∪ 3 ∖ 1 8
3 difundir ⊢ 1 ∪ 3 ∖ 1 8 = 1 ∖ 1 8 ∪ 3 ∖ 1 8
4 snsspr1 ⊢ 1 ⊆ 1 8
5 ssdif0 ⊢ 1 ⊆ 1 8 ↔ 1 ∖ 1 8 = ∅
6 4 5 mpbi ⊢ 1 ∖ 1 8 = ∅
7 incom ⊢ 3 ∩ 1 8 = 1 8 ∩ 3
8 1re ⊢ 1 ∈ ℝ
9 1lt3 ⊢ 1 < 3
10 8 9 gtneii ⊢ 3 ≠ 1
11 3re ⊢ 3 ∈ ℝ
12 3lt8 ⊢ 3 < 8
13 11 12 ltneii ⊢ 3 ≠ 8
14 10 13 nelpri ⊢ ¬ 3 ∈ 1 8
15 disjsn ⊢ 1 8 ∩ 3 = ∅ ↔ ¬ 3 ∈ 1 8
16 14 15 mpbir ⊢ 1 8 ∩ 3 = ∅
17 7 16 eqtri ⊢ 3 ∩ 1 8 = ∅
18 disj3 ⊢ 3 ∩ 1 8 = ∅ ↔ 3 = 3 ∖ 1 8
19 17 18 mpbi ⊢ 3 = 3 ∖ 1 8
20 19 eqcomi ⊢ 3 ∖ 1 8 = 3
21 6 20 uneq12i ⊢ 1 ∖ 1 8 ∪ 3 ∖ 1 8 = ∅ ∪ 3
22 uncom ⊢ ∅ ∪ 3 = 3 ∪ ∅
23 un0 ⊢ 3 ∪ ∅ = 3
24 21 22 23 3eqtri ⊢ 1 ∖ 1 8 ∪ 3 ∖ 1 8 = 3
25 2 3 24 3eqtri ⊢ 1 3 ∖ 1 8 = 3