Metamath Proof Explorer


Theorem expcnfg

Description: If F is a complex continuous function and N is a fixed number, then F^N is continuous too. A generalization of expcncf . (Contributed by Glauco Siliprandi, 29-Jun-2017)

Ref Expression
Hypotheses expcnfg.1 ⊢ Ⅎ _ x F
expcnfg.2 ⊢ φ → F : A ⟶cn ℂ
expcnfg.3 ⊢ φ → N ∈ ℕ 0
Assertion expcnfg ⊢ φ → x ∈ A ⟼ F ⁡ x N : A ⟶cn ℂ

Proof

Step Hyp Ref Expression
1 expcnfg.1 ⊢ Ⅎ _ x F
2 expcnfg.2 ⊢ φ → F : A ⟶cn ℂ
3 expcnfg.3 ⊢ φ → N ∈ ℕ 0
4 nfcv ⊢ Ⅎ _ t F ⁡ x N
5 nfcv ⊢ Ⅎ _ x t
6 1 5 nffv ⊢ Ⅎ _ x F ⁡ t
7 nfcv ⊢ Ⅎ _ x ^
8 nfcv ⊢ Ⅎ _ x N
9 6 7 8 nfov ⊢ Ⅎ _ x F ⁡ t N
10 fveq2 ⊢ x = t → F ⁡ x = F ⁡ t
11 10 oveq1d ⊢ x = t → F ⁡ x N = F ⁡ t N
12 4 9 11 cbvmpt ⊢ x ∈ A ⟼ F ⁡ x N = t ∈ A ⟼ F ⁡ t N
13 cncff ⊢ F : A ⟶cn ℂ → F : A ⟶ ℂ
14 2 13 syl ⊢ φ → F : A ⟶ ℂ
15 14 ffvelcdmda ⊢ φ ∧ t ∈ A → F ⁡ t ∈ ℂ
16 3 adantr ⊢ φ ∧ t ∈ A → N ∈ ℕ 0
17 15 16 expcld ⊢ φ ∧ t ∈ A → F ⁡ t N ∈ ℂ
18 oveq1 ⊢ x = F ⁡ t → x N = F ⁡ t N
19 eqid ⊢ x ∈ ℂ ⟼ x N = x ∈ ℂ ⟼ x N
20 6 9 18 19 fvmptf ⊢ F ⁡ t ∈ ℂ ∧ F ⁡ t N ∈ ℂ → x ∈ ℂ ⟼ x N ⁡ F ⁡ t = F ⁡ t N
21 15 17 20 syl2anc ⊢ φ ∧ t ∈ A → x ∈ ℂ ⟼ x N ⁡ F ⁡ t = F ⁡ t N
22 21 eqcomd ⊢ φ ∧ t ∈ A → F ⁡ t N = x ∈ ℂ ⟼ x N ⁡ F ⁡ t
23 22 mpteq2dva ⊢ φ → t ∈ A ⟼ F ⁡ t N = t ∈ A ⟼ x ∈ ℂ ⟼ x N ⁡ F ⁡ t
24 12 23 eqtrid ⊢ φ → x ∈ A ⟼ F ⁡ x N = t ∈ A ⟼ x ∈ ℂ ⟼ x N ⁡ F ⁡ t
25 simpr ⊢ φ ∧ x ∈ ℂ → x ∈ ℂ
26 3 adantr ⊢ φ ∧ x ∈ ℂ → N ∈ ℕ 0
27 25 26 expcld ⊢ φ ∧ x ∈ ℂ → x N ∈ ℂ
28 27 fmpttd ⊢ φ → x ∈ ℂ ⟼ x N : ℂ ⟶ ℂ
29 fcompt ⊢ x ∈ ℂ ⟼ x N : ℂ ⟶ ℂ ∧ F : A ⟶ ℂ → x ∈ ℂ ⟼ x N ∘ F = t ∈ A ⟼ x ∈ ℂ ⟼ x N ⁡ F ⁡ t
30 28 14 29 syl2anc ⊢ φ → x ∈ ℂ ⟼ x N ∘ F = t ∈ A ⟼ x ∈ ℂ ⟼ x N ⁡ F ⁡ t
31 24 30 eqtr4d ⊢ φ → x ∈ A ⟼ F ⁡ x N = x ∈ ℂ ⟼ x N ∘ F
32 expcncf ⊢ N ∈ ℕ 0 → x ∈ ℂ ⟼ x N : ℂ ⟶cn ℂ
33 3 32 syl ⊢ φ → x ∈ ℂ ⟼ x N : ℂ ⟶cn ℂ
34 2 33 cncfco ⊢ φ → x ∈ ℂ ⟼ x N ∘ F : A ⟶cn ℂ
35 31 34 eqeltrd ⊢ φ → x ∈ A ⟼ F ⁡ x N : A ⟶cn ℂ