Metamath Proof Explorer


Theorem exsnrex

Description: There is a set being the element of a singleton if and only if there is an element of the singleton. (Contributed by Alexander van der Vekens, 1-Jan-2018)

Ref Expression
Assertion exsnrex ⊢ ∃ x M = x ↔ ∃ x ∈ M M = x

Proof

Step Hyp Ref Expression
1 vsnid ⊢ x ∈ x
2 eleq2 ⊢ M = x → x ∈ M ↔ x ∈ x
3 1 2 mpbiri ⊢ M = x → x ∈ M
4 3 pm4.71ri ⊢ M = x ↔ x ∈ M ∧ M = x
5 4 exbii ⊢ ∃ x M = x ↔ ∃ x x ∈ M ∧ M = x
6 df-rex ⊢ ∃ x ∈ M M = x ↔ ∃ x x ∈ M ∧ M = x
7 5 6 bitr4i ⊢ ∃ x M = x ↔ ∃ x ∈ M M = x