Metamath Proof Explorer


Theorem f1od2

Description: Sufficient condition for a binary function expressed in maps-to notation to be bijective. (Contributed by Thierry Arnoux, 17-Aug-2017)

Ref Expression
Hypotheses f1od2.1 ⊢ F = x ∈ A , y ∈ B ⟼ C
f1od2.2 ⊢ φ ∧ x ∈ A ∧ y ∈ B → C ∈ W
f1od2.3 ⊢ φ ∧ z ∈ D → I ∈ X ∧ J ∈ Y
f1od2.4 ⊢ φ → x ∈ A ∧ y ∈ B ∧ z = C ↔ z ∈ D ∧ x = I ∧ y = J
Assertion f1od2 ⊢ φ → F : A × B ⟶ 1-1 onto D

Proof

Step Hyp Ref Expression
1 f1od2.1 ⊢ F = x ∈ A , y ∈ B ⟼ C
2 f1od2.2 ⊢ φ ∧ x ∈ A ∧ y ∈ B → C ∈ W
3 f1od2.3 ⊢ φ ∧ z ∈ D → I ∈ X ∧ J ∈ Y
4 f1od2.4 ⊢ φ → x ∈ A ∧ y ∈ B ∧ z = C ↔ z ∈ D ∧ x = I ∧ y = J
5 2 ralrimivva ⊢ φ → ∀ x ∈ A ∀ y ∈ B C ∈ W
6 1 fnmpo ⊢ ∀ x ∈ A ∀ y ∈ B C ∈ W → F Fn A × B
7 5 6 syl ⊢ φ → F Fn A × B
8 opelxpi ⊢ I ∈ X ∧ J ∈ Y → I J ∈ X × Y
9 3 8 syl ⊢ φ ∧ z ∈ D → I J ∈ X × Y
10 9 ralrimiva ⊢ φ → ∀ z ∈ D I J ∈ X × Y
11 eqid ⊢ z ∈ D ⟼ I J = z ∈ D ⟼ I J
12 11 fnmpt ⊢ ∀ z ∈ D I J ∈ X × Y → z ∈ D ⟼ I J Fn D
13 10 12 syl ⊢ φ → z ∈ D ⟼ I J Fn D
14 elxp7 ⊢ a ∈ A × B ↔ a ∈ V × V ∧ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B
15 14 anbi1i ⊢ a ∈ A × B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ a ∈ V × V ∧ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
16 anass ⊢ a ∈ V × V ∧ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ a ∈ V × V ∧ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
17 4 sbcbidv ⊢ φ → [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ z = C ↔ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ x = I ∧ y = J
18 17 sbcbidv ⊢ φ → [˙ 1 st ⁡ a / x]˙ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ z = C ↔ [˙ 1 st ⁡ a / x]˙ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ x = I ∧ y = J
19 sbcan ⊢ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ z = C ↔ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ [˙ 2 nd ⁡ a / y]˙ z = C
20 sbcan ⊢ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ↔ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ [˙ 2 nd ⁡ a / y]˙ y ∈ B
21 fvex ⊢ 2 nd ⁡ a ∈ V
22 sbcg ⊢ 2 nd ⁡ a ∈ V → [˙ 2 nd ⁡ a / y]˙ x ∈ A ↔ x ∈ A
23 21 22 ax-mp ⊢ [˙ 2 nd ⁡ a / y]˙ x ∈ A ↔ x ∈ A
24 sbcel1v ⊢ [˙ 2 nd ⁡ a / y]˙ y ∈ B ↔ 2 nd ⁡ a ∈ B
25 23 24 anbi12i ⊢ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ [˙ 2 nd ⁡ a / y]˙ y ∈ B ↔ x ∈ A ∧ 2 nd ⁡ a ∈ B
26 20 25 bitri ⊢ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ↔ x ∈ A ∧ 2 nd ⁡ a ∈ B
27 sbceq2g ⊢ 2 nd ⁡ a ∈ V → [˙ 2 nd ⁡ a / y]˙ z = C ↔ z = ⦋ 2 nd ⁡ a / y⦌ C
28 21 27 ax-mp ⊢ [˙ 2 nd ⁡ a / y]˙ z = C ↔ z = ⦋ 2 nd ⁡ a / y⦌ C
29 26 28 anbi12i ⊢ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ [˙ 2 nd ⁡ a / y]˙ z = C ↔ x ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 2 nd ⁡ a / y⦌ C
30 19 29 bitri ⊢ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ z = C ↔ x ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 2 nd ⁡ a / y⦌ C
31 30 sbcbii ⊢ [˙ 1 st ⁡ a / x]˙ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ z = C ↔ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 2 nd ⁡ a / y⦌ C
32 sbcan ⊢ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 2 nd ⁡ a / y⦌ C ↔ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ 2 nd ⁡ a ∈ B ∧ [˙ 1 st ⁡ a / x]˙ z = ⦋ 2 nd ⁡ a / y⦌ C
33 sbcan ⊢ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ 2 nd ⁡ a ∈ B ↔ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a ∈ B
34 sbcel1v ⊢ [˙ 1 st ⁡ a / x]˙ x ∈ A ↔ 1 st ⁡ a ∈ A
35 fvex ⊢ 1 st ⁡ a ∈ V
36 sbcg ⊢ 1 st ⁡ a ∈ V → [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a ∈ B ↔ 2 nd ⁡ a ∈ B
37 35 36 ax-mp ⊢ [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a ∈ B ↔ 2 nd ⁡ a ∈ B
38 34 37 anbi12i ⊢ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a ∈ B ↔ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B
39 33 38 bitri ⊢ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ 2 nd ⁡ a ∈ B ↔ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B
40 sbceq2g ⊢ 1 st ⁡ a ∈ V → [˙ 1 st ⁡ a / x]˙ z = ⦋ 2 nd ⁡ a / y⦌ C ↔ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
41 35 40 ax-mp ⊢ [˙ 1 st ⁡ a / x]˙ z = ⦋ 2 nd ⁡ a / y⦌ C ↔ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
42 39 41 anbi12i ⊢ [˙ 1 st ⁡ a / x]˙ x ∈ A ∧ 2 nd ⁡ a ∈ B ∧ [˙ 1 st ⁡ a / x]˙ z = ⦋ 2 nd ⁡ a / y⦌ C ↔ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
43 31 32 42 3bitri ⊢ [˙ 1 st ⁡ a / x]˙ [˙ 2 nd ⁡ a / y]˙ x ∈ A ∧ y ∈ B ∧ z = C ↔ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
44 sbcan ⊢ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ x = I ∧ y = J ↔ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ [˙ 2 nd ⁡ a / y]˙ x = I ∧ y = J
45 sbcg ⊢ 2 nd ⁡ a ∈ V → [˙ 2 nd ⁡ a / y]˙ z ∈ D ↔ z ∈ D
46 21 45 ax-mp ⊢ [˙ 2 nd ⁡ a / y]˙ z ∈ D ↔ z ∈ D
47 sbcan ⊢ [˙ 2 nd ⁡ a / y]˙ x = I ∧ y = J ↔ [˙ 2 nd ⁡ a / y]˙ x = I ∧ [˙ 2 nd ⁡ a / y]˙ y = J
48 sbcg ⊢ 2 nd ⁡ a ∈ V → [˙ 2 nd ⁡ a / y]˙ x = I ↔ x = I
49 21 48 ax-mp ⊢ [˙ 2 nd ⁡ a / y]˙ x = I ↔ x = I
50 sbceq1g ⊢ 2 nd ⁡ a ∈ V → [˙ 2 nd ⁡ a / y]˙ y = J ↔ ⦋ 2 nd ⁡ a / y⦌ y = J
51 21 50 ax-mp ⊢ [˙ 2 nd ⁡ a / y]˙ y = J ↔ ⦋ 2 nd ⁡ a / y⦌ y = J
52 21 csbvargi ⊢ ⦋ 2 nd ⁡ a / y⦌ y = 2 nd ⁡ a
53 52 eqeq1i ⊢ ⦋ 2 nd ⁡ a / y⦌ y = J ↔ 2 nd ⁡ a = J
54 51 53 bitri ⊢ [˙ 2 nd ⁡ a / y]˙ y = J ↔ 2 nd ⁡ a = J
55 49 54 anbi12i ⊢ [˙ 2 nd ⁡ a / y]˙ x = I ∧ [˙ 2 nd ⁡ a / y]˙ y = J ↔ x = I ∧ 2 nd ⁡ a = J
56 47 55 bitri ⊢ [˙ 2 nd ⁡ a / y]˙ x = I ∧ y = J ↔ x = I ∧ 2 nd ⁡ a = J
57 46 56 anbi12i ⊢ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ [˙ 2 nd ⁡ a / y]˙ x = I ∧ y = J ↔ z ∈ D ∧ x = I ∧ 2 nd ⁡ a = J
58 44 57 bitri ⊢ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ x = I ∧ y = J ↔ z ∈ D ∧ x = I ∧ 2 nd ⁡ a = J
59 58 sbcbii ⊢ [˙ 1 st ⁡ a / x]˙ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ x = I ∧ y = J ↔ [˙ 1 st ⁡ a / x]˙ z ∈ D ∧ x = I ∧ 2 nd ⁡ a = J
60 sbcan ⊢ [˙ 1 st ⁡ a / x]˙ z ∈ D ∧ x = I ∧ 2 nd ⁡ a = J ↔ [˙ 1 st ⁡ a / x]˙ z ∈ D ∧ [˙ 1 st ⁡ a / x]˙ x = I ∧ 2 nd ⁡ a = J
61 sbcg ⊢ 1 st ⁡ a ∈ V → [˙ 1 st ⁡ a / x]˙ z ∈ D ↔ z ∈ D
62 35 61 ax-mp ⊢ [˙ 1 st ⁡ a / x]˙ z ∈ D ↔ z ∈ D
63 sbcan ⊢ [˙ 1 st ⁡ a / x]˙ x = I ∧ 2 nd ⁡ a = J ↔ [˙ 1 st ⁡ a / x]˙ x = I ∧ [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a = J
64 sbceq1g ⊢ 1 st ⁡ a ∈ V → [˙ 1 st ⁡ a / x]˙ x = I ↔ ⦋ 1 st ⁡ a / x⦌ x = I
65 35 64 ax-mp ⊢ [˙ 1 st ⁡ a / x]˙ x = I ↔ ⦋ 1 st ⁡ a / x⦌ x = I
66 35 csbvargi ⊢ ⦋ 1 st ⁡ a / x⦌ x = 1 st ⁡ a
67 66 eqeq1i ⊢ ⦋ 1 st ⁡ a / x⦌ x = I ↔ 1 st ⁡ a = I
68 65 67 bitri ⊢ [˙ 1 st ⁡ a / x]˙ x = I ↔ 1 st ⁡ a = I
69 sbcg ⊢ 1 st ⁡ a ∈ V → [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a = J ↔ 2 nd ⁡ a = J
70 35 69 ax-mp ⊢ [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a = J ↔ 2 nd ⁡ a = J
71 68 70 anbi12i ⊢ [˙ 1 st ⁡ a / x]˙ x = I ∧ [˙ 1 st ⁡ a / x]˙ 2 nd ⁡ a = J ↔ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
72 63 71 bitri ⊢ [˙ 1 st ⁡ a / x]˙ x = I ∧ 2 nd ⁡ a = J ↔ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
73 62 72 anbi12i ⊢ [˙ 1 st ⁡ a / x]˙ z ∈ D ∧ [˙ 1 st ⁡ a / x]˙ x = I ∧ 2 nd ⁡ a = J ↔ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
74 59 60 73 3bitri ⊢ [˙ 1 st ⁡ a / x]˙ [˙ 2 nd ⁡ a / y]˙ z ∈ D ∧ x = I ∧ y = J ↔ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
75 18 43 74 3bitr3g ⊢ φ → 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
76 75 anbi2d ⊢ φ → a ∈ V × V ∧ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ a ∈ V × V ∧ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
77 16 76 bitrid ⊢ φ → a ∈ V × V ∧ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ a ∈ V × V ∧ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
78 xpss ⊢ X × Y ⊆ V × V
79 simprr ⊢ φ ∧ z ∈ D ∧ a = I J → a = I J
80 9 adantrr ⊢ φ ∧ z ∈ D ∧ a = I J → I J ∈ X × Y
81 79 80 eqeltrd ⊢ φ ∧ z ∈ D ∧ a = I J → a ∈ X × Y
82 78 81 sselid ⊢ φ ∧ z ∈ D ∧ a = I J → a ∈ V × V
83 82 ex ⊢ φ → z ∈ D ∧ a = I J → a ∈ V × V
84 83 pm4.71rd ⊢ φ → z ∈ D ∧ a = I J ↔ a ∈ V × V ∧ z ∈ D ∧ a = I J
85 eqop ⊢ a ∈ V × V → a = I J ↔ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
86 85 anbi2d ⊢ a ∈ V × V → z ∈ D ∧ a = I J ↔ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
87 86 pm5.32i ⊢ a ∈ V × V ∧ z ∈ D ∧ a = I J ↔ a ∈ V × V ∧ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J
88 84 87 bitr2di ⊢ φ → a ∈ V × V ∧ z ∈ D ∧ 1 st ⁡ a = I ∧ 2 nd ⁡ a = J ↔ z ∈ D ∧ a = I J
89 77 88 bitrd ⊢ φ → a ∈ V × V ∧ 1 st ⁡ a ∈ A ∧ 2 nd ⁡ a ∈ B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ z ∈ D ∧ a = I J
90 15 89 bitrid ⊢ φ → a ∈ A × B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ z ∈ D ∧ a = I J
91 90 opabbidv ⊢ φ → z a | a ∈ A × B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C = z a | z ∈ D ∧ a = I J
92 df-mpo ⊢ x ∈ A , y ∈ B ⟼ C = x y z | x ∈ A ∧ y ∈ B ∧ z = C
93 1 92 eqtri ⊢ F = x y z | x ∈ A ∧ y ∈ B ∧ z = C
94 93 cnveqi ⊢ F -1 = x y z | x ∈ A ∧ y ∈ B ∧ z = C -1
95 nfv ⊢ Ⅎ i x ∈ A ∧ y ∈ B ∧ z = C
96 nfv ⊢ Ⅎ j x ∈ A ∧ y ∈ B ∧ z = C
97 nfv ⊢ Ⅎ x i ∈ A ∧ j ∈ B
98 nfcsb1v ⊢ Ⅎ _ x ⦋ i / x⦌ ⦋ j / y⦌ C
99 98 nfeq2 ⊢ Ⅎ x z = ⦋ i / x⦌ ⦋ j / y⦌ C
100 97 99 nfan ⊢ Ⅎ x i ∈ A ∧ j ∈ B ∧ z = ⦋ i / x⦌ ⦋ j / y⦌ C
101 nfv ⊢ Ⅎ y i ∈ A ∧ j ∈ B
102 nfcv ⊢ Ⅎ _ y i
103 nfcsb1v ⊢ Ⅎ _ y ⦋ j / y⦌ C
104 102 103 nfcsbw ⊢ Ⅎ _ y ⦋ i / x⦌ ⦋ j / y⦌ C
105 104 nfeq2 ⊢ Ⅎ y z = ⦋ i / x⦌ ⦋ j / y⦌ C
106 101 105 nfan ⊢ Ⅎ y i ∈ A ∧ j ∈ B ∧ z = ⦋ i / x⦌ ⦋ j / y⦌ C
107 simpl ⊢ x = i ∧ y = j → x = i
108 107 eleq1d ⊢ x = i ∧ y = j → x ∈ A ↔ i ∈ A
109 simpr ⊢ x = i ∧ y = j → y = j
110 109 eleq1d ⊢ x = i ∧ y = j → y ∈ B ↔ j ∈ B
111 108 110 anbi12d ⊢ x = i ∧ y = j → x ∈ A ∧ y ∈ B ↔ i ∈ A ∧ j ∈ B
112 csbeq1a ⊢ y = j → C = ⦋ j / y⦌ C
113 csbeq1a ⊢ x = i → ⦋ j / y⦌ C = ⦋ i / x⦌ ⦋ j / y⦌ C
114 112 113 sylan9eqr ⊢ x = i ∧ y = j → C = ⦋ i / x⦌ ⦋ j / y⦌ C
115 114 eqeq2d ⊢ x = i ∧ y = j → z = C ↔ z = ⦋ i / x⦌ ⦋ j / y⦌ C
116 111 115 anbi12d ⊢ x = i ∧ y = j → x ∈ A ∧ y ∈ B ∧ z = C ↔ i ∈ A ∧ j ∈ B ∧ z = ⦋ i / x⦌ ⦋ j / y⦌ C
117 95 96 100 106 116 cbvoprab12 ⊢ x y z | x ∈ A ∧ y ∈ B ∧ z = C = i j z | i ∈ A ∧ j ∈ B ∧ z = ⦋ i / x⦌ ⦋ j / y⦌ C
118 117 cnveqi ⊢ x y z | x ∈ A ∧ y ∈ B ∧ z = C -1 = i j z | i ∈ A ∧ j ∈ B ∧ z = ⦋ i / x⦌ ⦋ j / y⦌ C -1
119 eleq1 ⊢ a = i j → a ∈ A × B ↔ i j ∈ A × B
120 opelxp ⊢ i j ∈ A × B ↔ i ∈ A ∧ j ∈ B
121 119 120 bitrdi ⊢ a = i j → a ∈ A × B ↔ i ∈ A ∧ j ∈ B
122 csbcom ⊢ ⦋ 2 nd ⁡ a / j⦌ ⦋ i / x⦌ ⦋ j / y⦌ C = ⦋ i / x⦌ ⦋ 2 nd ⁡ a / j⦌ ⦋ j / y⦌ C
123 csbcow ⊢ ⦋ 2 nd ⁡ a / j⦌ ⦋ j / y⦌ C = ⦋ 2 nd ⁡ a / y⦌ C
124 123 csbeq2i ⊢ ⦋ i / x⦌ ⦋ 2 nd ⁡ a / j⦌ ⦋ j / y⦌ C = ⦋ i / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
125 122 124 eqtri ⊢ ⦋ 2 nd ⁡ a / j⦌ ⦋ i / x⦌ ⦋ j / y⦌ C = ⦋ i / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
126 125 csbeq2i ⊢ ⦋ 1 st ⁡ a / i⦌ ⦋ 2 nd ⁡ a / j⦌ ⦋ i / x⦌ ⦋ j / y⦌ C = ⦋ 1 st ⁡ a / i⦌ ⦋ i / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
127 csbcow ⊢ ⦋ 1 st ⁡ a / i⦌ ⦋ i / x⦌ ⦋ 2 nd ⁡ a / y⦌ C = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
128 126 127 eqtri ⊢ ⦋ 1 st ⁡ a / i⦌ ⦋ 2 nd ⁡ a / j⦌ ⦋ i / x⦌ ⦋ j / y⦌ C = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
129 csbopeq1a ⊢ a = i j → ⦋ 1 st ⁡ a / i⦌ ⦋ 2 nd ⁡ a / j⦌ ⦋ i / x⦌ ⦋ j / y⦌ C = ⦋ i / x⦌ ⦋ j / y⦌ C
130 128 129 eqtr3id ⊢ a = i j → ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C = ⦋ i / x⦌ ⦋ j / y⦌ C
131 130 eqeq2d ⊢ a = i j → z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ z = ⦋ i / x⦌ ⦋ j / y⦌ C
132 121 131 anbi12d ⊢ a = i j → a ∈ A × B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C ↔ i ∈ A ∧ j ∈ B ∧ z = ⦋ i / x⦌ ⦋ j / y⦌ C
133 xpss ⊢ A × B ⊆ V × V
134 133 sseli ⊢ a ∈ A × B → a ∈ V × V
135 134 adantr ⊢ a ∈ A × B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C → a ∈ V × V
136 132 135 cnvoprab ⊢ i j z | i ∈ A ∧ j ∈ B ∧ z = ⦋ i / x⦌ ⦋ j / y⦌ C -1 = z a | a ∈ A × B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
137 94 118 136 3eqtri ⊢ F -1 = z a | a ∈ A × B ∧ z = ⦋ 1 st ⁡ a / x⦌ ⦋ 2 nd ⁡ a / y⦌ C
138 df-mpt ⊢ z ∈ D ⟼ I J = z a | z ∈ D ∧ a = I J
139 91 137 138 3eqtr4g ⊢ φ → F -1 = z ∈ D ⟼ I J
140 139 fneq1d ⊢ φ → F -1 Fn D ↔ z ∈ D ⟼ I J Fn D
141 13 140 mpbird ⊢ φ → F -1 Fn D
142 dff1o4 ⊢ F : A × B ⟶ 1-1 onto D ↔ F Fn A × B ∧ F -1 Fn D
143 7 141 142 sylanbrc ⊢ φ → F : A × B ⟶ 1-1 onto D