Metamath Proof Explorer


Theorem f1oeq3d

Description: Equality deduction for one-to-one onto functions. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Hypothesis f1oeq3d.1 ⊢ φ → A = B
Assertion f1oeq3d ⊢ φ → F : C ⟶ 1-1 onto A ↔ F : C ⟶ 1-1 onto B

Proof

Step Hyp Ref Expression
1 f1oeq3d.1 ⊢ φ → A = B
2 f1oeq3 ⊢ A = B → F : C ⟶ 1-1 onto A ↔ F : C ⟶ 1-1 onto B
3 1 2 syl ⊢ φ → F : C ⟶ 1-1 onto A ↔ F : C ⟶ 1-1 onto B