Metamath Proof Explorer


Theorem ffs2

Description: Rewrite a function's support based with its codomain rather than the universal class. See also fsuppeq . (Contributed by Thierry Arnoux, 27-Aug-2017) (Revised by Thierry Arnoux, 1-Sep-2019)

Ref Expression
Hypothesis ffs2.1 ⊢ C = B ∖ Z
Assertion ffs2 ⊢ A ∈ V ∧ Z ∈ W ∧ F : A ⟶ B → F supp Z = F -1 C

Proof

Step Hyp Ref Expression
1 ffs2.1 ⊢ C = B ∖ Z
2 fsuppeq ⊢ A ∈ V ∧ Z ∈ W → F : A ⟶ B → F supp Z = F -1 B ∖ Z
3 2 3impia ⊢ A ∈ V ∧ Z ∈ W ∧ F : A ⟶ B → F supp Z = F -1 B ∖ Z
4 1 imaeq2i ⊢ F -1 C = F -1 B ∖ Z
5 3 4 eqtr4di ⊢ A ∈ V ∧ Z ∈ W ∧ F : A ⟶ B → F supp Z = F -1 C