Metamath Proof Explorer


Theorem ffvbr

Description: Relation with function value. (Contributed by Zhi Wang, 25-Nov-2025)

Ref Expression
Assertion ffvbr ⊢ F : A ⟶ B ∧ X ∈ A → X F F ⁡ X

Proof

Step Hyp Ref Expression
1 simpl ⊢ F : A ⟶ B ∧ X ∈ A → F : A ⟶ B
2 1 ffund ⊢ F : A ⟶ B ∧ X ∈ A → Fun ⁡ F
3 simpr ⊢ F : A ⟶ B ∧ X ∈ A → X ∈ A
4 1 fdmd ⊢ F : A ⟶ B ∧ X ∈ A → dom ⁡ F = A
5 3 4 eleqtrrd ⊢ F : A ⟶ B ∧ X ∈ A → X ∈ dom ⁡ F
6 funfvbrb ⊢ Fun ⁡ F → X ∈ dom ⁡ F ↔ X F F ⁡ X
7 6 biimpa ⊢ Fun ⁡ F ∧ X ∈ dom ⁡ F → X F F ⁡ X
8 2 5 7 syl2anc ⊢ F : A ⟶ B ∧ X ∈ A → X F F ⁡ X