Metamath Proof Explorer


Theorem fldgenfld

Description: A generated subfield is a field. (Contributed by Thierry Arnoux, 11-Jan-2025)

Ref Expression
Hypotheses fldgenfld.1 ⊢ B = Base F
fldgenfld.2 ⊢ φ → F ∈ Field
fldgenfld.3 ⊢ φ → S ⊆ B
Assertion fldgenfld ⊢ φ → F ↾ 𝑠 F fldGen S ∈ Field

Proof

Step Hyp Ref Expression
1 fldgenfld.1 ⊢ B = Base F
2 fldgenfld.2 ⊢ φ → F ∈ Field
3 fldgenfld.3 ⊢ φ → S ⊆ B
4 isfld ⊢ F ∈ Field ↔ F ∈ DivRing ∧ F ∈ CRing
5 2 4 sylib ⊢ φ → F ∈ DivRing ∧ F ∈ CRing
6 5 simpld ⊢ φ → F ∈ DivRing
7 1 6 3 fldgensdrg ⊢ φ → F fldGen S ∈ SubDRing ⁡ F
8 fldsdrgfld ⊢ F ∈ Field ∧ F fldGen S ∈ SubDRing ⁡ F → F ↾ 𝑠 F fldGen S ∈ Field
9 2 7 8 syl2anc ⊢ φ → F ↾ 𝑠 F fldGen S ∈ Field