Metamath Proof Explorer


Theorem fldgenidfld

Description: The subfield generated by a subfield is the subfield itself. (Contributed by Thierry Arnoux, 15-Jan-2025)

Ref Expression
Hypotheses fldgenval.1 ⊢ B = Base F
fldgenval.2 ⊢ φ → F ∈ DivRing
fldgenidfld.s ⊢ φ → S ∈ SubDRing ⁡ F
Assertion fldgenidfld ⊢ φ → F fldGen S = S

Proof

Step Hyp Ref Expression
1 fldgenval.1 ⊢ B = Base F
2 fldgenval.2 ⊢ φ → F ∈ DivRing
3 fldgenidfld.s ⊢ φ → S ∈ SubDRing ⁡ F
4 1 sdrgss ⊢ S ∈ SubDRing ⁡ F → S ⊆ B
5 3 4 syl ⊢ φ → S ⊆ B
6 1 2 5 fldgenval ⊢ φ → F fldGen S = ⋂ a ∈ SubDRing ⁡ F | S ⊆ a
7 intmin ⊢ S ∈ SubDRing ⁡ F → ⋂ a ∈ SubDRing ⁡ F | S ⊆ a = S
8 3 7 syl ⊢ φ → ⋂ a ∈ SubDRing ⁡ F | S ⊆ a = S
9 6 8 eqtrd ⊢ φ → F fldGen S = S