Metamath Proof Explorer


Theorem fn0

Description: A function with empty domain is empty. (Contributed by NM, 15-Apr-1998) (Proof shortened by Andrew Salmon, 17-Sep-2011)

Ref Expression
Assertion fn0 F Fn F =

Proof

Step Hyp Ref Expression
1 fnrel F Fn Rel F
2 fndm F Fn dom F =
3 reldm0 Rel F F = dom F =
4 3 biimpar Rel F dom F = F =
5 1 2 4 syl2anc F Fn F =
6 fun0 Fun
7 dm0 dom =
8 df-fn Fn Fun dom =
9 6 7 8 mpbir2an Fn
10 fneq1 F = F Fn Fn
11 9 10 mpbiri F = F Fn
12 5 11 impbii F Fn F =