Metamath Proof Explorer
Description: If a function is a set, its domain is a set. (Contributed by Rohan
Ridenour, 13-May-2024)
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|
Ref |
Expression |
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Hypotheses |
fndmexd.1 |
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fndmexd.2 |
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Assertion |
fndmexd |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
fndmexd.1 |
|
2 |
|
fndmexd.2 |
|
3 |
2
|
fndmd |
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4 |
1
|
dmexd |
|
5 |
3 4
|
eqeltrrd |
|