Metamath Proof Explorer


Theorem fndmu

Description: A function has a unique domain. (Contributed by NM, 11-Aug-1994)

Ref Expression
Assertion fndmu F Fn A F Fn B A = B

Proof

Step Hyp Ref Expression
1 fndm F Fn A dom F = A
2 fndm F Fn B dom F = B
3 1 2 sylan9req F Fn A F Fn B A = B