Metamath Proof Explorer


Theorem fourierdlem13

Description: Value of V in terms of value of Q . (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses fourierdlem13.a ⊢ φ → A ∈ ℝ
fourierdlem13.b ⊢ φ → B ∈ ℝ
fourierdlem13.x ⊢ φ → X ∈ ℝ
fourierdlem13.p ⊢ P = m ∈ ℕ ⟼ p ∈ ℝ 0 … m | p ⁡ 0 = A + X ∧ p ⁡ m = B + X ∧ ∀ i ∈ 0 ..^ m p ⁡ i < p ⁡ i + 1
fourierdlem13.m ⊢ φ → M ∈ ℕ
fourierdlem13.v ⊢ φ → V ∈ P ⁡ M
fourierdlem13.i ⊢ φ → I ∈ 0 … M
fourierdlem13.q ⊢ Q = i ∈ 0 … M ⟼ V ⁡ i − X
Assertion fourierdlem13 ⊢ φ → Q ⁡ I = V ⁡ I − X ∧ V ⁡ I = X + Q ⁡ I

Proof

Step Hyp Ref Expression
1 fourierdlem13.a ⊢ φ → A ∈ ℝ
2 fourierdlem13.b ⊢ φ → B ∈ ℝ
3 fourierdlem13.x ⊢ φ → X ∈ ℝ
4 fourierdlem13.p ⊢ P = m ∈ ℕ ⟼ p ∈ ℝ 0 … m | p ⁡ 0 = A + X ∧ p ⁡ m = B + X ∧ ∀ i ∈ 0 ..^ m p ⁡ i < p ⁡ i + 1
5 fourierdlem13.m ⊢ φ → M ∈ ℕ
6 fourierdlem13.v ⊢ φ → V ∈ P ⁡ M
7 fourierdlem13.i ⊢ φ → I ∈ 0 … M
8 fourierdlem13.q ⊢ Q = i ∈ 0 … M ⟼ V ⁡ i − X
9 8 a1i ⊢ φ → Q = i ∈ 0 … M ⟼ V ⁡ i − X
10 simpr ⊢ φ ∧ i = I → i = I
11 10 fveq2d ⊢ φ ∧ i = I → V ⁡ i = V ⁡ I
12 11 oveq1d ⊢ φ ∧ i = I → V ⁡ i − X = V ⁡ I − X
13 4 fourierdlem2 ⊢ M ∈ ℕ → V ∈ P ⁡ M ↔ V ∈ ℝ 0 … M ∧ V ⁡ 0 = A + X ∧ V ⁡ M = B + X ∧ ∀ i ∈ 0 ..^ M V ⁡ i < V ⁡ i + 1
14 5 13 syl ⊢ φ → V ∈ P ⁡ M ↔ V ∈ ℝ 0 … M ∧ V ⁡ 0 = A + X ∧ V ⁡ M = B + X ∧ ∀ i ∈ 0 ..^ M V ⁡ i < V ⁡ i + 1
15 6 14 mpbid ⊢ φ → V ∈ ℝ 0 … M ∧ V ⁡ 0 = A + X ∧ V ⁡ M = B + X ∧ ∀ i ∈ 0 ..^ M V ⁡ i < V ⁡ i + 1
16 15 simpld ⊢ φ → V ∈ ℝ 0 … M
17 elmapi ⊢ V ∈ ℝ 0 … M → V : 0 … M ⟶ ℝ
18 16 17 syl ⊢ φ → V : 0 … M ⟶ ℝ
19 18 7 ffvelcdmd ⊢ φ → V ⁡ I ∈ ℝ
20 19 3 resubcld ⊢ φ → V ⁡ I − X ∈ ℝ
21 9 12 7 20 fvmptd ⊢ φ → Q ⁡ I = V ⁡ I − X
22 21 oveq2d ⊢ φ → X + Q ⁡ I = X + V ⁡ I - X
23 3 recnd ⊢ φ → X ∈ ℂ
24 19 recnd ⊢ φ → V ⁡ I ∈ ℂ
25 23 24 pncan3d ⊢ φ → X + V ⁡ I - X = V ⁡ I
26 22 25 eqtr2d ⊢ φ → V ⁡ I = X + Q ⁡ I
27 21 26 jca ⊢ φ → Q ⁡ I = V ⁡ I − X ∧ V ⁡ I = X + Q ⁡ I