Metamath Proof Explorer


Theorem fourierdlem23

Description: If F is continuous and X is constant, then ( F( X + s ) ) is continuous. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses fourierdlem23.a φA
fourierdlem23.f φF:Acn
fourierdlem23.b φB
fourierdlem23.x φX
fourierdlem23.xps φsBX+sA
Assertion fourierdlem23 φsBFX+s:Bcn

Proof

Step Hyp Ref Expression
1 fourierdlem23.a φA
2 fourierdlem23.f φF:Acn
3 fourierdlem23.b φB
4 fourierdlem23.x φX
5 fourierdlem23.xps φsBX+sA
6 eqid sBX+s=sBX+s
7 6 addccncf2 BXsBX+s:Bcn
8 3 4 7 syl2anc φsBX+s:Bcn
9 ssid BB
10 9 a1i φBB
11 6 8 10 1 5 cncfmptssg φsBX+s:BcnA
12 11 2 cncfcompt φsBFX+s:Bcn