Metamath Proof Explorer


Theorem fprodeq02

Description: If one of the factors is zero the product is zero. (Contributed by Thierry Arnoux, 11-Dec-2021)

Ref Expression
Hypotheses fprodeq02.1 ⊢ k = K → B = C
fprodeq02.a ⊢ φ → A ∈ Fin
fprodeq02.b ⊢ φ ∧ k ∈ A → B ∈ ℂ
fprodeq02.k ⊢ φ → K ∈ A
fprodeq02.c ⊢ φ → C = 0
Assertion fprodeq02 ⊢ φ → ∏ k ∈ A B = 0

Proof

Step Hyp Ref Expression
1 fprodeq02.1 ⊢ k = K → B = C
2 fprodeq02.a ⊢ φ → A ∈ Fin
3 fprodeq02.b ⊢ φ ∧ k ∈ A → B ∈ ℂ
4 fprodeq02.k ⊢ φ → K ∈ A
5 fprodeq02.c ⊢ φ → C = 0
6 disjdif ⊢ K ∩ A ∖ K = ∅
7 6 a1i ⊢ φ → K ∩ A ∖ K = ∅
8 4 snssd ⊢ φ → K ⊆ A
9 undif ⊢ K ⊆ A ↔ K ∪ A ∖ K = A
10 8 9 sylib ⊢ φ → K ∪ A ∖ K = A
11 10 eqcomd ⊢ φ → A = K ∪ A ∖ K
12 7 11 2 3 fprodsplit ⊢ φ → ∏ k ∈ A B = ∏ k ∈ K B ⁢ ∏ k ∈ A ∖ K B
13 0cnd ⊢ φ → 0 ∈ ℂ
14 5 13 eqeltrd ⊢ φ → C ∈ ℂ
15 1 prodsn ⊢ K ∈ A ∧ C ∈ ℂ → ∏ k ∈ K B = C
16 4 14 15 syl2anc ⊢ φ → ∏ k ∈ K B = C
17 16 5 eqtrd ⊢ φ → ∏ k ∈ K B = 0
18 17 oveq1d ⊢ φ → ∏ k ∈ K B ⁢ ∏ k ∈ A ∖ K B = 0 ⋅ ∏ k ∈ A ∖ K B
19 diffi ⊢ A ∈ Fin → A ∖ K ∈ Fin
20 2 19 syl ⊢ φ → A ∖ K ∈ Fin
21 difssd ⊢ φ → A ∖ K ⊆ A
22 21 sselda ⊢ φ ∧ k ∈ A ∖ K → k ∈ A
23 22 3 syldan ⊢ φ ∧ k ∈ A ∖ K → B ∈ ℂ
24 20 23 fprodcl ⊢ φ → ∏ k ∈ A ∖ K B ∈ ℂ
25 24 mul02d ⊢ φ → 0 ⋅ ∏ k ∈ A ∖ K B = 0
26 12 18 25 3eqtrd ⊢ φ → ∏ k ∈ A B = 0