Metamath Proof Explorer


Theorem frgpeccl

Description: Closure of the quotient map in a free group. (Contributed by Mario Carneiro, 1-Oct-2015)

Ref Expression
Hypotheses frgp0.m ⊢ G = freeGrp ⁡ I
frgp0.r ⊢ ∼ ˙ = ~ FG ⁡ I
frgpeccl.w ⊢ W = I ⁡ Word I × 2 𝑜
frgpeccl.b ⊢ B = Base G
Assertion frgpeccl ⊢ X ∈ W → X ∼ ˙ ∈ B

Proof

Step Hyp Ref Expression
1 frgp0.m ⊢ G = freeGrp ⁡ I
2 frgp0.r ⊢ ∼ ˙ = ~ FG ⁡ I
3 frgpeccl.w ⊢ W = I ⁡ Word I × 2 𝑜
4 frgpeccl.b ⊢ B = Base G
5 2 fvexi ⊢ ∼ ˙ ∈ V
6 5 ecelqsi ⊢ X ∈ W → X ∼ ˙ ∈ W / ∼ ˙
7 3 efgrcl ⊢ X ∈ W → I ∈ V ∧ W = Word I × 2 𝑜
8 7 simpld ⊢ X ∈ W → I ∈ V
9 eqid ⊢ freeMnd ⁡ I × 2 𝑜 = freeMnd ⁡ I × 2 𝑜
10 1 9 2 frgpval ⊢ I ∈ V → G = freeMnd ⁡ I × 2 𝑜 / 𝑠 ∼ ˙
11 8 10 syl ⊢ X ∈ W → G = freeMnd ⁡ I × 2 𝑜 / 𝑠 ∼ ˙
12 7 simprd ⊢ X ∈ W → W = Word I × 2 𝑜
13 2on ⊢ 2 𝑜 ∈ On
14 xpexg ⊢ I ∈ V ∧ 2 𝑜 ∈ On → I × 2 𝑜 ∈ V
15 8 13 14 sylancl ⊢ X ∈ W → I × 2 𝑜 ∈ V
16 eqid ⊢ Base freeMnd ⁡ I × 2 𝑜 = Base freeMnd ⁡ I × 2 𝑜
17 9 16 frmdbas ⊢ I × 2 𝑜 ∈ V → Base freeMnd ⁡ I × 2 𝑜 = Word I × 2 𝑜
18 15 17 syl ⊢ X ∈ W → Base freeMnd ⁡ I × 2 𝑜 = Word I × 2 𝑜
19 12 18 eqtr4d ⊢ X ∈ W → W = Base freeMnd ⁡ I × 2 𝑜
20 5 a1i ⊢ X ∈ W → ∼ ˙ ∈ V
21 fvexd ⊢ X ∈ W → freeMnd ⁡ I × 2 𝑜 ∈ V
22 11 19 20 21 qusbas ⊢ X ∈ W → W / ∼ ˙ = Base G
23 22 4 eqtr4di ⊢ X ∈ W → W / ∼ ˙ = B
24 6 23 eleqtrd ⊢ X ∈ W → X ∼ ˙ ∈ B