Metamath Proof Explorer


Theorem frlmiscvec

Description: Every free module is isomorphic to the free module of "column vectors" of the same dimension over the same (nonzero) ring. (Contributed by AV, 10-Mar-2019)

Ref Expression
Assertion frlmiscvec ⊢ R ∈ NzRing ∧ I ∈ Y → R freeLMod I ≃ 𝑚 R freeLMod I × ∅

Proof

Step Hyp Ref Expression
1 simpr ⊢ R ∈ NzRing ∧ I ∈ Y → I ∈ Y
2 0ex ⊢ ∅ ∈ V
3 xpsneng ⊢ I ∈ Y ∧ ∅ ∈ V → I × ∅ ≈ I
4 3 ensymd ⊢ I ∈ Y ∧ ∅ ∈ V → I ≈ I × ∅
5 1 2 4 sylancl ⊢ R ∈ NzRing ∧ I ∈ Y → I ≈ I × ∅
6 frlmisfrlm ⊢ R ∈ NzRing ∧ I ∈ Y ∧ I ≈ I × ∅ → R freeLMod I ≃ 𝑚 R freeLMod I × ∅
7 5 6 mpd3an3 ⊢ R ∈ NzRing ∧ I ∈ Y → R freeLMod I ≃ 𝑚 R freeLMod I × ∅