Metamath Proof Explorer


Theorem func1st

Description: Extract the first member of a functor. (Contributed by Zhi Wang, 15-Nov-2025)

Ref Expression
Hypothesis func1st.1 ⊢ φ → F C Func D G
Assertion func1st ⊢ φ → 1 st ⁡ F G = F

Proof

Step Hyp Ref Expression
1 func1st.1 ⊢ φ → F C Func D G
2 relfunc ⊢ Rel ⁡ C Func D
3 2 brrelex12i ⊢ F C Func D G → F ∈ V ∧ G ∈ V
4 op1stg ⊢ F ∈ V ∧ G ∈ V → 1 st ⁡ F G = F
5 1 3 4 3syl ⊢ φ → 1 st ⁡ F G = F