Metamath Proof Explorer


Theorem func2nd

Description: Extract the second member of a functor. (Contributed by Zhi Wang, 15-Nov-2025)

Ref Expression
Hypothesis func1st.1 ⊢ φ → F C Func D G
Assertion func2nd ⊢ φ → 2 nd ⁡ F G = G

Proof

Step Hyp Ref Expression
1 func1st.1 ⊢ φ → F C Func D G
2 relfunc ⊢ Rel ⁡ C Func D
3 2 brrelex12i ⊢ F C Func D G → F ∈ V ∧ G ∈ V
4 op2ndg ⊢ F ∈ V ∧ G ∈ V → 2 nd ⁡ F G = G
5 1 3 4 3syl ⊢ φ → 2 nd ⁡ F G = G