Metamath Proof Explorer


Theorem funeq

Description: Equality theorem for function predicate. (Contributed by NM, 16-Aug-1994)

Ref Expression
Assertion funeq A = B Fun A Fun B

Proof

Step Hyp Ref Expression
1 eqimss2 A = B B A
2 funss B A Fun A Fun B
3 1 2 syl A = B Fun A Fun B
4 eqimss A = B A B
5 funss A B Fun B Fun A
6 4 5 syl A = B Fun B Fun A
7 3 6 impbid A = B Fun A Fun B