Metamath Proof Explorer


Theorem funimass4f

Description: Membership relation for the values of a function whose image is a subclass. (Contributed by Thierry Arnoux, 24-Apr-2017)

Ref Expression
Hypotheses funimass4f.1 ⊢ Ⅎ _ x A
funimass4f.2 ⊢ Ⅎ _ x B
funimass4f.3 ⊢ Ⅎ _ x F
Assertion funimass4f ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F → F A ⊆ B ↔ ∀ x ∈ A F ⁡ x ∈ B

Proof

Step Hyp Ref Expression
1 funimass4f.1 ⊢ Ⅎ _ x A
2 funimass4f.2 ⊢ Ⅎ _ x B
3 funimass4f.3 ⊢ Ⅎ _ x F
4 3 nffun ⊢ Ⅎ x Fun ⁡ F
5 3 nfdm ⊢ Ⅎ _ x dom ⁡ F
6 1 5 nfss ⊢ Ⅎ x A ⊆ dom ⁡ F
7 4 6 nfan ⊢ Ⅎ x Fun ⁡ F ∧ A ⊆ dom ⁡ F
8 3 1 nfima ⊢ Ⅎ _ x F A
9 8 2 nfss ⊢ Ⅎ x F A ⊆ B
10 7 9 nfan ⊢ Ⅎ x Fun ⁡ F ∧ A ⊆ dom ⁡ F ∧ F A ⊆ B
11 funfvima2 ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F → x ∈ A → F ⁡ x ∈ F A
12 ssel ⊢ F A ⊆ B → F ⁡ x ∈ F A → F ⁡ x ∈ B
13 11 12 sylan9 ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F ∧ F A ⊆ B → x ∈ A → F ⁡ x ∈ B
14 10 13 ralrimi ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F ∧ F A ⊆ B → ∀ x ∈ A F ⁡ x ∈ B
15 1 3 dfimafnf ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F → F A = y | ∃ x ∈ A y = F ⁡ x
16 15 adantr ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F ∧ ∀ x ∈ A F ⁡ x ∈ B → F A = y | ∃ x ∈ A y = F ⁡ x
17 2 abrexss ⊢ ∀ x ∈ A F ⁡ x ∈ B → y | ∃ x ∈ A y = F ⁡ x ⊆ B
18 17 adantl ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F ∧ ∀ x ∈ A F ⁡ x ∈ B → y | ∃ x ∈ A y = F ⁡ x ⊆ B
19 16 18 eqsstrd ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F ∧ ∀ x ∈ A F ⁡ x ∈ B → F A ⊆ B
20 14 19 impbida ⊢ Fun ⁡ F ∧ A ⊆ dom ⁡ F → F A ⊆ B ↔ ∀ x ∈ A F ⁡ x ∈ B