Metamath Proof Explorer


Theorem fvco

Description: Value of a function composition. Similar to Exercise 5 of TakeutiZaring p. 28. (Contributed by NM, 22-Apr-2006) (Proof shortened by Mario Carneiro, 26-Dec-2014)

Ref Expression
Assertion fvco ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → F ∘ G ⁡ A = F ⁡ G ⁡ A

Proof

Step Hyp Ref Expression
1 funfn ⊢ Fun ⁡ G ↔ G Fn dom ⁡ G
2 fvco2 ⊢ G Fn dom ⁡ G ∧ A ∈ dom ⁡ G → F ∘ G ⁡ A = F ⁡ G ⁡ A
3 1 2 sylanb ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → F ∘ G ⁡ A = F ⁡ G ⁡ A