Metamath Proof Explorer


Theorem fvfundmfvn0

Description: If the "value of a class" at an argument is not the empty set, then the argument is in the domain of the class and the class restricted to the singleton formed on that argument is a function. (Contributed by Alexander van der Vekens, 26-May-2017) (Proof shortened by BJ, 13-Aug-2022)

Ref Expression
Assertion fvfundmfvn0 F A A dom F Fun F A

Proof

Step Hyp Ref Expression
1 ndmfv ¬ A dom F F A =
2 1 necon1ai F A A dom F
3 nfunsn ¬ Fun F A F A =
4 3 necon1ai F A Fun F A
5 2 4 jca F A A dom F Fun F A