Metamath Proof Explorer


Theorem fz1sumconst

Description: The sum of N constant terms ( k is not free in C ). (Contributed by SN, 21-Mar-2025)

Ref Expression
Hypotheses fz1sumconst.n ⊢ φ → N ∈ ℕ 0
fz1sumconst.c ⊢ φ → C ∈ ℂ
Assertion fz1sumconst ⊢ φ → ∑ k = 1 N C = N ⁢ C

Proof

Step Hyp Ref Expression
1 fz1sumconst.n ⊢ φ → N ∈ ℕ 0
2 fz1sumconst.c ⊢ φ → C ∈ ℂ
3 fzfi ⊢ 1 … N ∈ Fin
4 fsumconst ⊢ 1 … N ∈ Fin ∧ C ∈ ℂ → ∑ k = 1 N C = 1 … N ⁢ C
5 3 2 4 sylancr ⊢ φ → ∑ k = 1 N C = 1 … N ⁢ C
6 hashfz1 ⊢ N ∈ ℕ 0 → 1 … N = N
7 1 6 syl ⊢ φ → 1 … N = N
8 7 oveq1d ⊢ φ → 1 … N ⁢ C = N ⁢ C
9 5 8 eqtrd ⊢ φ → ∑ k = 1 N C = N ⁢ C